Consider a set of 11 numbers Value-I = Minimum value of the average of the numbers of the set when they are consecutive integers…

Question

Consider a set of 11 numbers:

Value-I = Minimum value of the average of the numbers of the set when they are consecutive integers ≥ −5.

Value-II = Minimum value of the product of the numbers of the set when they are consecutive non-negative integers.

Which one of the following is correct?

1. A. Value-I < Value-II
2. B. Value-II < Value-I
3. C. Value-I = Value-II (Correct answer)
4. D. Cannot be determined due to insufficient data

Correct Answer

Option C — Value-I = Value-II

Detailed Solution & Explanation

The correct answer is Value-I = Value-II.

Key Points

• 11 consecutive integers ≥ −5: minimum average when starting at −5: {−5,−4,...,5}.
• Average = 0. Value-I = 0. 11 consecutive non-negative integers with minimum product: {0,1,2,...,10} → product = 0 (contains zero).
• Value-II = 0. Value-I = Value-II = 0. Answer: Value-I = Value-II.