Q74. The number of red balls in A and E together is what percentage of the number of blue balls in A and E together?

Question

Directions (74-79):

Table shows total balls in 5 bags with difference between red & blue and % of red balls.

Bag A: diff=60, red%=62.5% → Total=240, Red=150, Blue=90

Bag B: diff=198, red%=66.5% → Total=600, Red=399, Blue=201

Bag C: diff=188, red%=70% → Total=470, Red=329, Blue=141

Bag D: diff=76, red%=60% → Total=380, Red=228, Blue=152

Bag E: diff=330, red%=72% → Total=750, Red=540, Blue=210

Q74. The number of red balls in A and E together is what percentage of the number of blue balls in A and E together?

1. A. 230 (Correct answer)
2. B. 220
3. C. 240
4. D. 280
5. E. 260

Correct Answer

Option A — 230

Detailed Solution & Explanation

The correct answer is 230.

Key Points

• Table: Bag A — 240 balls (150 red, 90 blue); Bag B — 600 (399 red, 201 blue); Bag C — 470 (329 red, 141 blue); Bag D — 380 (228 red, 152 blue); Bag E — 750 (540 red, 210 blue).
• Each bag's red/blue split is found from the given red-minus-blue difference and percentage of red balls.
• Red balls in A and E together = 150 + 540 = 690.
• Blue balls in A and E together = 90 + 210 = 300.
• Required percentage = (690 ÷ 300) × 100 = 230%.
• 'X is what percentage of Y' means (X ÷ Y) × 100.
• Here the reds outnumber the blues, so the answer naturally exceeds 100%.

Exam Tip

• in data-interpretation sets, first extract each bag's exact red and blue counts from the difference-and-percentage clues, tabulate them once, and then every sub-question is a quick arithmetic lookup.