Given below are two statements: Statement-I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 27…
Chemistry ·Previously asked in NEET UG 2025
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Question
Given below are two statements:
Statement-I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state. Statement-II: Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI. In the light of the above statements, choose the most appropriate answer from the options given below:
- A. Both Statement I and Statement II are correct (Correct answer)
- B. Both Statement I and Statement II are incorrect
- C. Statement I is correct but Statement II is incorrect
- D. Statement I is incorrect but Statement II is correct
Correct Answer
Option A — Both Statement I and Statement II are correct
Detailed Solution & Explanation
The correct answer is Both Statement I and Statement II are correct.
Key Points
- Benzenediazonium chloride is prepared by diazotisation of aniline with nitrous acid (NaNO$_2$ + HCl) at 273-278 K, and it decomposes readily when dry — Statement I is correct.
- Direct iodination of benzene is difficult, so iodobenzene is made by treating benzenediazonium salt with KI (releasing N$_2$) — Statement II is correct.
Topics covered: NEET UG 2025 Chemistry Amines Diazonium Salts