If the molar conductivity (m) of a 0.050 mol L^-1 solution of a monobasic weak acid is 90 S cm^2 mol^-1, its extent (degree) of dissociation will be [Assume λ^+=349.6 S cm^2 mol^-1 and λ^-=50.4 S cm^2 mol^-1]:
A. 0.115
B. 0.125
C. 0.225 (Correct answer)
D. 0.215
Correct Answer
Option C — 0.225
Detailed Solution & Explanation
The correct answer is 0.225.
Key Points
Degree of dissociation $\alpha=\dfrac{\Lambda_m}{\Lambda_m^\circ}$.
$\Lambda_m^\circ=\Lambda^\circ_++\Lambda^\circ_-=349.6+50.4=400$ S cm$^2$ mol$^{-1}$.