The standard heat of formation, in kcal/mol, of Ba^2+ is: [Given: standard heat of formation of SO4^2- ion (aq) = -216 kcal/mol,…
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Question
The standard heat of formation, in kcal/mol, of Ba^2+ is: [Given: standard heat of formation of SO4^2- ion (aq) = -216 kcal/mol, standard heat of crystallisation of BaSO4(s) = -4.5 kcal/mol, standard heat of formation of BaSO4(s) = -349 kcal/mol]
- A. -128.5 (Correct answer)
- B. -133.0
- C. +133.0
- D. +220.5
Correct Answer
Option A — -128.5
Detailed Solution & Explanation
The correct answer is -128.5 kcal/mol.
Key Points
- Combine: (1) formation of SO$_4^{2-}$ ($-216$), (2) crystallisation Ba$^{2+}$(g) + SO$_4^{2-}$(g) $\to$ BaSO$_4$ ($-4.5$), (3) formation of BaSO$_4$(s) ($-349$).
- $\Delta H_f(\text{Ba}^{2+})=\Delta H_f(\text{BaSO}_4)-\Delta H_f(\text{SO}_4^{2-})-\Delta H_{cryst}$.
- $=-349-(-216)-(-4.5)=-349+216+4.5=-128.5$ kcal/mol.
Topics covered: NEET UG 2025 Chemistry Thermodynamics Hess's Law