A dealer sells a product at 15% profit. If he had bought it at 10% less and sold it for ₹126 less, he would have gained 20%. Find…
Mathematics ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
A dealer sells a product at 15% profit. If he had bought it at 10% less and sold it for ₹126 less, he would have gained 20%. Find the cost price.
- A. ₹1,400
- B. ₹1,800 (Correct answer)
- C. ₹2,000
- D. ₹1,200
Correct Answer
Option B — ₹1,800
Detailed Solution & Explanation
The correct answer is ₹1,800.
Shortcut Trick
- Work in units instead of rupees and the arithmetic collapses to one division.
- Assume the original CP = 100 units. Then the original SP = 115 units (15% profit).
- New CP is 10% less, so CP₂ = 90 units. A 20% gain on that gives SP₂ = 90 × 1.20 = 108 units.
- Difference in selling price = 115 − 108 = 7 units, and the question tells us that difference is ₹126.
- So 7 units = ₹126 → 1 unit = ₹18, and the original CP of 100 units = ₹1,800.
Alternate Method
- Let the cost price be ₹x.
- Original selling price: $SP_1 = 1.15x$
- Reduced cost price: $CP_2 = 0.90x$
- New selling price at 20% gain: $SP_2 = 0.90x \times 1.20 = 1.08x$
- Given $SP_1 - SP_2 = 126$:
- $1.15x - 1.08x = 126$
- $0.07x = 126$
- $x = 126 \div 0.07 = \textbf{1800}$
Additional Information
- Profit % $= \dfrac{\text{Profit}}{CP} \times 100$, and $SP = CP \times \dfrac{100 + \text{Profit\%}}{100}$.
- Successive percentage change: a change of $a\%$ followed by $b\%$ gives a net change of $\left(a + b + \dfrac{ab}{100}\right)\%$. Here a 10% fall in CP with a 20% gain nets $-10 + 20 - 2 = +8\%$, which is why $SP_2 = 1.08x$ directly.
- The unit method works whenever the question gives only percentages plus one absolute figure — assume 100, compute the difference in units, then scale.
Topics covered: Profit and Loss Mathematics