A fruit seller sold mangoes at ₹600 per box last month. This month, he first increased the price by 10% due to transportation cos…
Mathematics ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
A fruit seller sold mangoes at ₹600 per box last month. This month, he first increased the price by 10% due to transportation costs and then offered a discount of 15% on the increased price. What is the final price of one box of mangoes?
- A. ₹571
- B. ₹541
- C. ₹561 (Correct answer)
- D. ₹551
Correct Answer
Option C — ₹561
Detailed Solution & Explanation
The correct answer is ₹561.
Shortcut Trick
- Combine the two changes into a single multiplier instead of computing each step in rupees.
- A 10% rise then a 15% discount gives $1.10 \times 0.85 = 0.935$.
- Final price $= 600 \times 0.935 = \textbf{₹561}$.
Alternate Method
- Increased price $= 600 + 10\% \text{ of } 600 = 600 + 60 = ₹660$
- Discount $= 15\% \text{ of } 660 = ₹99$
- Final price $= 660 - 99 = \textbf{₹561}$
Additional Information
- Successive changes never simply add. A 10% rise followed by a 15% fall is not −5%; by the net-change formula it is $10 - 15 - \dfrac{10 \times 15}{100} = -6.5\%$, and indeed $600 \times 0.935 = 561$, a fall of ₹39 = 6.5%.
- Order does not matter for successive multiplicative changes: $1.10 \times 0.85 = 0.85 \times 1.10$. Raising then discounting gives the same result as discounting then raising.
- The multiplier method scales to any number of changes — just multiply the factors, which is far faster than working through each stage in rupees.
Topics covered: Percentage Mathematics