A question paper consists of four questions, each having two possible answers, YES or NO. In how many different ways can a studen…
Basic Numeracy ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025
View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)
Question
A question paper consists of four questions, each having two possible answers, YES or NO.
In how many different ways can a student answer at least one question?
- A. 81
- B. 16
- C. 15
- D. 80 (Correct answer)
Correct Answer
Option D — 80
Detailed Solution & Explanation
The correct answer is 80.
Key Points
- For each question a student may answer YES, answer NO, or leave it unattempted — 3 possibilities per question.
- With four independent questions that gives 3⁴ = 81 total patterns.
- Exactly one of these leaves every question unattempted, and it must be excluded because at least one question is to be answered.
- So the count = 81 − 1 = 80.
Additional Information
- The distractor 16 (= 2⁴) counts only fully-attempted papers; 15 subtracts one from that, and 81 forgets to exclude the blank paper.
- The phrase *at least one* almost always signals the complement method: count everything, then remove the single 'none' case.
*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*
Topics covered: Permutation & Combination Worked Solution