A question paper consists of four questions, each having two possible answers, YES or NO. In how many different ways can a studen…

Basic Numeracy ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025

View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)

Question

A question paper consists of four questions, each having two possible answers, YES or NO.

In how many different ways can a student answer at least one question?

  1. A. 81
  2. B. 16
  3. C. 15
  4. D. 80 (Correct answer)

Correct Answer

Option D — 80

Detailed Solution & Explanation

The correct answer is 80.

Key Points

  • For each question a student may answer YES, answer NO, or leave it unattempted — 3 possibilities per question.
  • With four independent questions that gives 3⁴ = 81 total patterns.
  • Exactly one of these leaves every question unattempted, and it must be excluded because at least one question is to be answered.
  • So the count = 81 − 1 = 80.

Additional Information

  • The distractor 16 (= 2⁴) counts only fully-attempted papers; 15 subtracts one from that, and 81 forgets to exclude the blank paper.
  • The phrase *at least one* almost always signals the complement method: count everything, then remove the single 'none' case.

*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*

Topics covered: Permutation & Combination Worked Solution