A right circular cone has a radius of 7 cm and height of 24 cm. What is the slant height?
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I (12 Sep, Shift 3)
Question
A right circular cone has a radius of 7 cm and height of 24 cm. What is the slant height?
- A. 25 cm (Correct answer)
- B. 30 cm
- C. 35 cm
- D. 40 cm
Correct Answer
Option A — 25 cm
Detailed Solution & Explanation
The correct answer is 25 cm.
Key Points
- The radius, height and slant height of a right circular cone form a right triangle, so l² = r² + h².
- Substituting: l² = 7² + 24² = 49 + 576 = 625, giving l = 25 cm.
- (7, 24, 25) is a standard Pythagorean triple; recognising it removes the arithmetic entirely.
- Related cone formulae worth keeping together: curved surface area = πrl, total surface area = πr(l + r) and volume = (1/3)πr²h.
- Other triples that recur in mensuration: (3, 4, 5), (5, 12, 13), (8, 15, 17) and (9, 40, 41).
Additional Information
- Cone formulae: slant height l = √(r² + h²), curved surface area = πrl, total surface area = πr(l + r) and volume = (1/3)πr²h.
- A cone's volume is exactly one-third of the cylinder with the same base and height — a relation frequently tested directly.
- Pythagorean triples worth recognising on sight: (3,4,5), (5,12,13), (7,24,25), (8,15,17), (9,40,41) and (20,21,29), along with their multiples.
प्रश्न (हिन्दी में)
एक लम्ब वृत्तीय शंकु की त्रिज्या 7 सेमी और ऊँचाई 24 सेमी है। तिर्यक ऊँचाई क्या है?
- A. 25 सेमी
- B. 30 सेमी
- C. 35 सेमी
- D. 40 सेमी
Topics covered: Mensuration Cone