Evaluate: \(6 - [2/3 ÷ \1/6 + (1/2× (1 - 1/3))\]\)
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I - 13 Sep 2025, Shift 1 (13 Sep 2025, Shift 1)
Question
Evaluate: \(6 - [2/3 ÷ \1/6 + (1/2× (1 - 1/3))\]\)
- A. \(14/3\) (Correct answer)
- B. \(15/3\)
- C. \(16/3\)
- D. \(17/3\)
Correct Answer
Option A — \(14/3\)
Detailed Solution & Explanation
The correct answer is 14/3.
Key Points
- Work strictly outward from the innermost bracket:
- 1 − 1/3 = 2/3
- 1/2 × 2/3 = 1/3
- 1/6 + 1/3 = 1/6 + 2/6 = 1/2
- 2/3 ÷ 1/2 = 2/3 × 2/1 = 4/3
- 6 − 4/3 = 18/3 − 4/3 = 14/3
Additional Information
- The bracket hierarchy is ( ) → { } → [ ], innermost first — the "B" of BODMAS, and the whole point of this question.
- Dividing by a fraction means multiplying by its reciprocal: a ÷ (b/c) = a × (c/b).
- Note that option B, 15/3, simplifies to 5 — options are sometimes left unsimplified to disguise a familiar value, so reduce every option mentally before comparing.
- Convert whole numbers to the common denominator before the final subtraction; writing 6 as 18/3 prevents the commonest slip here.
प्रश्न (हिन्दी में)
मूल्यांकन कीजिए: \(6 - [2/3 ÷ \1/6 + (1/2× (1 - 1/3))\]\)
- A. \(14/3\)
- B. \(15/3\)
- C. \(16/3\)
- D. \(17/3\)
Topics covered: Simplification BODMAS