Given \(x + 1/x = 5\) , determine the value of \(x^2 + 1/x^2\) .
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I - 13 Sep 2025, Shift 2 (13 Sep 2025, Shift 2)
Question
Given \(x + 1/x = 5\) , determine the value of \(x^2 + 1/x^2\) .
- A. 25
- B. 24
- C. 26
- D. 23 (Correct answer)
Correct Answer
Option D — 23
Detailed Solution & Explanation
The correct answer is 23.
Key Points
- Square both sides of the given equation, using (a + b)² = a² + 2ab + b²:
- (x + 1/x)² = x² + 2·x·(1/x) + 1/x² = x² + 2 + 1/x²
- Since x + 1/x = 5, the left side is 25:
- x² + 1/x² + 2 = 25 → x² + 1/x² = 23
Additional Information
- The middle term is always 2, because x × 1/x = 1 — that cancellation is what makes this family of identities work.
- The standard results worth memorising:
- If x + 1/x = a, then x² + 1/x² = a² − 2 and x³ + 1/x³ = a³ − 3a
- If x − 1/x = a, then x² + 1/x² = a² + 2
- Here x³ + 1/x³ would be 125 − 15 = 110, a frequent follow-up.
- Option A (25) is the trap for anyone who squares without subtracting the middle term.
प्रश्न (हिन्दी में)
दिया है \(x + 1/x = 5\) , तो \(x^2 + 1/x^2\) का मान ज्ञात करें।
- A. 25
- B. 24
- C. 26
- D. 23
Topics covered: Algebraic Identities Simplification