If \(a\ \%\ b = 37\) , where \(a\ \%\ b = a + 2b\) , what is the value of a and b?
General Intelligence & Reasoning ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I (12 Sep, Shift 3)
Question
If \(a\ \%\ b = 37\) , where \(a\ \%\ b = a + 2b\) , what is the value of a and b?
- A. 25, 5
- B. 27, 5 (Correct answer)
- C. 16, 10
- D. 27, 10
Correct Answer
Option B — 27, 5
Detailed Solution & Explanation
The correct answer is 27, 5.
Key Points
- The rule is given: a % b = a + 2b, and the result must be 37.
- Testing the options: 27 + 2(5) = 27 + 10 = 37 ✓.
- The others miss: 25 + 10 = 35, 16 + 20 = 36, 27 + 20 = 47.
- When the operation is defined explicitly, substitute the options straight into it — there is nothing to deduce.
- Because the operation is defined for you, substitution is faster than algebra — but if you prefer solving, a = 37 − 2b immediately shows b = 5 gives the whole-number pair 27, 5.
- Check every option rather than stopping at the first near-miss; 27 appears in two options, distinguished only by the value of b.
Additional Information
- Where the operation is defined explicitly, substituting the options is faster than algebra, since only four candidates exist.
- Check every option rather than stopping at the first near-miss; options are often built to share one value and differ in the other.
- If you prefer solving directly, rearranging to a = 37 − 2b and testing small whole numbers for b reaches the pair just as quickly.
प्रश्न (हिन्दी में)
यदि \(a\ \%\ b = 37\) है, जहाँ \(a\ \%\ b = a + 2b\) , तो a और b का मान क्या है?
- A. 25, 5
- B. 27, 5
- C. 16, 10
- D. 27, 10
Topics covered: Operator Substitution Algebra