If 16 + 11 = A and 1/9 = B , and A\ \%\ B = (A × B) - 1 , then what is A\ \%\ B ?

Question

If 16 + 11 = A and 1/9 = B , and A\ \%\ B = (A × B) - 1 , then what is A\ \%\ B ?

1. A. 0
2. B. -3
3. C. 2 (Correct answer)
4. D. 5

Correct Answer

Option C — 2

Detailed Solution & Explanation

The correct answer is 2.

Key Points

• Evaluate the given values first: A = 16 + 11 = 27 and B = 1/9.
• The defined operation is A % B = (A × B) − 1.
• So A % B = (27 × 1/9) − 1 = 3 − 1 = 2.

Additional Information

• The % here is a defined symbol, not the ordinary percentage or modulus — invented-operator questions always redefine familiar signs.
• Substitute the numbers before applying the definition; trying to simplify the expression symbolically first invites sign errors.
• Multiplying by 1/9 is the same as dividing by 9, which is why 27 collapses neatly to 3.

प्रश्न (हिन्दी में)

यदि 16 + 11 = A और 1/9 = B , तथा A\ \%\ B = (A × B) - 1 है, तो A\ \%\ B क्या है?

1. A. 0
2. B. -3
3. C. 2
4. D. 5