If x = 2 + √3/2 - √3 , determine the value of x^2 + x - 9 .
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I — 12 Sep 2025 (Shift 2)
Question
If x = 2 + √3/2 - √3 , determine the value of x^2 + x - 9 .
- A. 3√3
- B. 5√3 (Correct answer)
- C. 7√3
- D. 9√3
Correct Answer
Option B — 5√3
Detailed Solution & Explanation
The correct answer is 5√3.
Key Points
- Rationalise inside the radical first: multiply top and bottom by $2 + \sqrt{3}$.
- $\dfrac{2 + \sqrt{3}}{2 - \sqrt{3}} = \dfrac{(2 + \sqrt{3})^2}{4 - 3} = (2 + \sqrt{3})^2$.
- Taking the square root gives $x = 2 + \sqrt{3}$, so $x^2 = 7 + 4\sqrt{3}$.
- Then $x^2 + x - 9 = (7 + 4\sqrt{3}) + (2 + \sqrt{3}) - 9 = 5\sqrt{3}$.
Additional Information
- The denominator $4 - 3 = 1$ is what makes the expression collapse so neatly — that is the designed shortcut.
- Numeric check: $x \approx 3.732$, $x^2 \approx 13.93$, and $13.93 + 3.73 - 9 \approx 8.66 = 5\sqrt{3}$ ✓
- Multiplying by the conjugate is the standard move whenever a surd sits in a denominator.
प्रश्न (हिन्दी में)
यदि x = 2 + √3/2 - √3 , तो x^2 + x - 9 का मान ज्ञात कीजिए।
- A. 3√3
- B. 5√3
- C. 7√3
- D. 9√3
Topics covered: SSC CGL Quantitative Aptitude Quantitative Aptitude SSC CGL 12 Sep 2025 Q73