If sinθ / x = cosθ / y, then sinθ − cosθ is:
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier II (19 Jan 2026)
Question
If sinθ / x = cosθ / y, then sinθ − cosθ is:
- A. (x − y) / (2√(x² + y²))
- B. (x − y) / √(3x² + 5y²)
- C. (5x − y) / (3√(x² + y²))
- D. (x − y) / √(x² + y²) (Correct answer)
Correct Answer
Option D — (x − y) / √(x² + y²)
Detailed Solution & Explanation
The correct answer is (x − y) / √(x² + y²).
Key Points
- Set the equal ratios to a constant k:
- sinθ/x = cosθ/y = k, so sinθ = kx and cosθ = ky
- Apply the Pythagorean identity:
- sin²θ + cos²θ = 1 → k²(x² + y²) = 1 → k = 1/√(x² + y²)
- Therefore sinθ − cosθ = k(x − y) = (x − y) / √(x² + y²).
Additional Information
- Introducing a constant of proportionality is the standard move whenever two ratios are stated equal — it converts a relationship into two usable expressions.
- The identity sin²θ + cos²θ = 1 is what pins k down; without it the problem is underdetermined.
- The same setup gives sinθ + cosθ = (x + y)/√(x² + y²), and multiplying the two results yields (x² − y²)/(x² + y²).
- Note that k could be negative depending on the quadrant, but the options assume the principal positive root, as is conventional in these questions.
Topics covered: Trigonometry Identities