If the interest on a sum of ₹y at 10% per annum compounded annually for 2 years is ₹462, then the total amount payable at the end…
Mathematics ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
If the interest on a sum of ₹y at 10% per annum compounded annually for 2 years is ₹462, then the total amount payable at the end of the two-year period will be .
- A. ₹2,762
- B. ₹2,962
- C. ₹2,662 (Correct answer)
- D. ₹2,862
Correct Answer
Option C — ₹2,662
Detailed Solution & Explanation
The correct answer is ₹2,662.
Shortcut Trick
- For 2 years at $r\%$, compound interest is a fixed fraction of the principal: $\left[(1+r)^2 - 1\right]$. At 10% that is $1.21 - 1 = 0.21$, i.e. 21% of P.
- $0.21P = 462 \Rightarrow P = ₹2{,}200$.
- Amount $=$ principal $+$ interest $= 2200 + 462 = \textbf{₹2,662}$.
Alternate Method
- $A = P\left(1 + \dfrac{r}{100}\right)^n = P(1.1)^2 = 1.21P$
- $CI = A - P = 0.21P = 462 \Rightarrow P = 2200$
- $A = 1.21 \times 2200 = \textbf{₹2,662}$
Additional Information
- Two-year shortcuts worth memorising: at $r\%$, the two-year CI is $\left(2r + \dfrac{r^2}{100}\right)\%$ of the principal — at 10% that is $20 + 1 = 21\%$, matching above.
- CI always exceeds SI, and for 2 years the gap is exactly $P\left(\dfrac{r}{100}\right)^2$. Here $2200 \times 0.01 = ₹22$, so SI would be ₹440 against CI ₹462.
- The question asks for the amount, not the interest. Adding the interest back is the step most often missed under time pressure.
Topics covered: Compound Interest Mathematics