Q99. A set of four consecutive multiples of 4 has an average of 30. The lowest number of another series of 5 consecutive even num…

Question

Q99. A set of four consecutive multiples of 4 has an average of 30. The lowest number of another series of 5 consecutive even numbers equals the second lowest multiple from the first series. Find the highest number of the 5 consecutive even numbers.

1. A. 36 (Correct answer)
2. B. 34
3. C. 32
4. D. 30
5. E. 38

Correct Answer

Option A — 36

Detailed Solution & Explanation

The correct answer is 36.

Key Points

• Four consecutive multiples of 4 with avg 30: let them be 4n, 4n+4, 4n+8, 4n+12 → avg = 4n+6 = 30 → n=6 → multiples: 24,28,32,36. Second lowest = 28. Five consecutive even numbers starting from 28: 28,30,32,34,36. Highest = 36.