Simplify: \12/33 ÷ 12/2\ ÷ (3/7 × 14/9 + 3/11) + 2/8 ÷ 31/25 of 25/8
Mathematics ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
Simplify:
\12/33 ÷ 12/2\ ÷ (3/7 × 14/9 + 3/11) + 2/8 ÷ 31/25 of 25/8
- A. 4/31 (Correct answer)
- B. 5/36
- C. 7/38
- D. 5/24
Correct Answer
Option A — 4/31
Detailed Solution & Explanation
The correct answer is $\dfrac{4}{31}$.
Shortcut Trick
- Resolve the two groupings separately; each collapses to a small fraction.
- Braces: $\dfrac{12}{33} \div \dfrac{12}{2} = \dfrac{12}{33} \times \dfrac{2}{12} = \dfrac{2}{33}$
- Parentheses: $\dfrac{3}{7} \times \dfrac{14}{9} + \dfrac{3}{11} = \dfrac{2}{3} + \dfrac{3}{11} = \dfrac{22 + 9}{33} = \dfrac{31}{33}$
- Dividing: $\dfrac{2}{33} \div \dfrac{31}{33} = \dfrac{2}{31}$
- "of" binds first: $\dfrac{31}{25} \text{ of } \dfrac{25}{8} = \dfrac{31}{8}$, so $\dfrac{2}{8} \div \dfrac{31}{8} = \dfrac{2}{31}$
- Total $= \dfrac{2}{31} + \dfrac{2}{31} = \dfrac{\textbf{4}}{\textbf{31}}$
Alternate Method
- Notice the symmetry: both halves of the expression reduce to $\dfrac{2}{31}$. Spotting that after computing the first half lets you double it rather than working the second through.
- The design is deliberate — the 33s cancel in the first half and the 8s in the second.
Additional Information
- "of" is treated as multiplication but binds more tightly than division in this convention, so $\frac{2}{8} \div \frac{31}{25}$ of $\frac{25}{8}$ means $\frac{2}{8} \div \left(\frac{31}{25} \times \frac{25}{8}\right)$, not $\left(\frac{2}{8} \div \frac{31}{25}\right) \times \frac{25}{8}$. Reading it the second way gives a different answer entirely.
- Bracket order is braces { } → parentheses ( ) → the rest, worked inside out.
- Cancel before multiplying at every step; carrying $\frac{45}{60}$-style products through a long chain is where arithmetic slips creep in.
Topics covered: Simplification Mathematics