Which of the following numbers is completely divisible by 6?
Mathematics ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
Which of the following numbers is completely divisible by 6?
- A. 5,47,821
- B. 7,53,216 (Correct answer)
- C. 8,91,452
- D. 6,42,538
Correct Answer
Option B — 7,53,216
Detailed Solution & Explanation
The correct answer is 7,53,216.
Shortcut Trick
- $6 = 2 \times 3$, so the number must be even and have a digit sum divisible by 3.
- Eliminate on the easier test first — parity: 5,47,821 ends in 1, so it fails immediately.
- Of the remaining even numbers, check digit sums:
- $7{,}53{,}216 \Rightarrow 7+5+3+2+1+6 = 24$ ✓ divisible by 3
- $8{,}91{,}452 \Rightarrow 29$ ✗
- $6{,}42{,}538 \Rightarrow 28$ ✗
- Only 7,53,216 passes both.
Alternate Method
- Direct division confirms it: $753216 \div 6 = 125536$ exactly, with no remainder.
Additional Information
- Test the cheapest condition first. Checking parity takes a glance and removed one option here before any addition was needed.
- Composite divisors split into coprime factors: $6 = 2 \times 3$, $12 = 3 \times 4$, $15 = 3 \times 5$, $24 = 3 \times 8$. Splitting $12$ as $2 \times 6$ would be invalid, since 2 and 6 share a factor.
- A number divisible by 6 is automatically divisible by 2 and 3, but the converse needs both — being even alone is never sufficient.
Topics covered: Divisibility Mathematics