If (i). 84 ÷ 21 = 9 ; (ii). 56 ÷ 32 = 6 ; (iii). 37 ÷ 41 = 5

Logical Reasoning & Analytical Ability ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025

View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)

Question

If (i). 84 ÷ 21 = 9 ; (ii). 56 ÷ 32 = 6 ; (iii). 37 ÷ 41 = 5

The above operations are done using some logic.

Using same logic find number replaces '?' in the following:

87 ÷ 15 = ?

  1. A. 0
  2. B. 9 (Correct answer)
  3. C. 7
  4. D. 3

Correct Answer

Option B — 9

Detailed Solution & Explanation

The correct answer is 9.

Key Points

  • Treat each two-digit number as a pair of digits, then compute (sum of the first number's digits) − (sum of the second number's digits).
  • Check (i): 84 and 21 → (8 + 4) − (2 + 1) = 12 − 3 = 9
  • Check (ii): 56 and 32 → (5 + 6) − (3 + 2) = 11 − 5 = 6
  • Check (iii): 37 and 41 → (3 + 7) − (4 + 1) = 10 − 5 = 5
  • Apply to 87 and 15: (8 + 7) − (1 + 5) = 15 − 6 = 9.

Additional Information

  • The '÷' sign here is a decoy — the operation has nothing to do with division. Coded-operation questions routinely reuse familiar symbols for invented rules.
  • Always validate a candidate rule against every worked example before applying it; a rule that fits two of three examples is the wrong rule.

*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*

Topics covered: Number Logic Worked Solution