If 5 © 4 = 41, 7 © 2 = 53, 11 © 3 = 130, then what is the value of 8 © 5?
Logical Reasoning & Analytical Ability ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025
View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)
Question
Find the correct logic from the given equations and, based on the same logic, solve the following:
If 5 © 4 = 41, 7 © 2 = 53, 11 © 3 = 130, then what is the value of 8 © 5?
Choose the correct answer:
- A. 78
- B. 63
- C. 56
- D. 89 (Correct answer)
Correct Answer
Option D — 89
Detailed Solution & Explanation
The correct answer is 89.
Key Points
- The operator © combines the two numbers as a² + b².
- Check: 5 © 4 = 25 + 16 = 41 ✓
- Check: 7 © 2 = 49 + 4 = 53 ✓
- Check: 11 © 3 = 121 + 9 = 130 ✓
- So 8 © 5 = 64 + 25 = 89.
Additional Information
- The distractor 78 comes from a² + b² read as a² + 2b or similar near-miss rules; always verify a candidate rule on all three given equations.
- Squares worth having ready: 8² = 64, 11² = 121, 13² = 169.
*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*
Topics covered: Number Logic Worked Solution