If 5 © 4 = 41, 7 © 2 = 53, 11 © 3 = 130, then what is the value of 8 © 5?

Logical Reasoning & Analytical Ability ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025

View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)

Question

Find the correct logic from the given equations and, based on the same logic, solve the following:

If 5 © 4 = 41, 7 © 2 = 53, 11 © 3 = 130, then what is the value of 8 © 5?

Choose the correct answer:

  1. A. 78
  2. B. 63
  3. C. 56
  4. D. 89 (Correct answer)

Correct Answer

Option D — 89

Detailed Solution & Explanation

The correct answer is 89.

Key Points

  • The operator © combines the two numbers as a² + b².
  • Check: 5 © 4 = 25 + 16 = 41
  • Check: 7 © 2 = 49 + 4 = 53
  • Check: 11 © 3 = 121 + 9 = 130
  • So 8 © 5 = 64 + 25 = 89.

Additional Information

  • The distractor 78 comes from a² + b² read as a² + 2b or similar near-miss rules; always verify a candidate rule on all three given equations.
  • Squares worth having ready: 8² = 64, 11² = 121, 13² = 169.

*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*

Topics covered: Number Logic Worked Solution