From a 64-liter container of pure spirit, 8 liters are removed and replaced by water. This operation is performed a total of thre…
Quantitative Aptitude ·Previously asked in SSC CGL 2025
View the full solved paper: SSC CGL 2025 Tier I - 13 Sep 2025, Shift 1 (13 Sep 2025, Shift 1)
Question
From a 64-liter container of pure spirit, 8 liters are removed and replaced by water. This operation is performed a total of three times. What is the final quantity of spirit remaining in the container?
- A. 34.34 liters
- B. 36.45 liters
- C. 38.62 liters
- D. 42.88 liters (Correct answer)
Correct Answer
Option D — 42.88 liters
Detailed Solution & Explanation
The correct answer is 42.88 liters.
Key Points
- For repeated removal and replacement, the quantity of the original liquid remaining is:
- Final = Initial × (1 − x/T)ⁿ, where x is removed each time from total T, over n operations.
- Substituting: 64 × (1 − 8/64)³ = 64 × (7/8)³.
- (7/8)³ = 343/512, so 64 × 343/512 = 42.875 ≈ 42.88 litres.
Additional Information
- The key insight is that each operation removes the same fraction of whatever spirit remains, not the same quantity — which is why the result is a geometric decay rather than a linear one.
- After three operations the spirit is 343/512 of the original, roughly 67%, so the water content is about 33%.
- The same formula covers milk-and-water replacement, alcohol dilution and any repeated-substitution problem; the only care needed is that x and T share units.
प्रश्न (हिन्दी में)
शुद्ध स्पिरिट के 64 लीटर के कंटेनर से 8 लीटर निकाल कर उसकी जगह पानी डाला जाता है। यह प्रक्रिया कुल तीन बार की जाती है। कंटेनर में बची हुई स्पिरिट की अंतिम मात्रा क्या है?
- A. 34.34 लीटर
- B. 36.45 लीटर
- C. 38.62 लीटर
- D. 42.88 लीटर
Topics covered: Mixture & Alligation Replacement