If 2 is added to each even digit and 2 is subtracted from each odd digit in the number 5973642, then what will be the sum of all…
General Intelligence & Reasoning ·Previously asked in RRB NTPC 2026
View the full solved paper: RRB NTPC UG 2026 (7 May, Shift 1)
Question
If 2 is added to each even digit and 2 is subtracted from each odd digit in the number 5973642, then what will be the sum of all the even digits in the new number thus formed?
- A. 24
- B. 20
- C. 16
- D. 18 (Correct answer)
Correct Answer
Option D — 18
Detailed Solution & Explanation
The correct answer is 18.
Key Points
- Apply the rule digit by digit to 5973642 — add 2 to each even digit, subtract 2 from each odd digit:
- 5 (odd) → 3, 9 (odd) → 7, 7 (odd) → 5, 3 (odd) → 1
- 6 (even) → 8, 4 (even) → 6, 2 (even) → 4
- The new number is 3751864.
- Now identify the even digits in the new number: 8, 6 and 4, giving $8 + 6 + 4 = \textbf{18}$.
Additional Information
- The trap is answering with the even digits of the original number. Those were 6, 4 and 2, which after transformation are the ones that stayed even — but a candidate who sums the originals gets $6+4+2 = 12$, and one who sums all new digits gets 34.
- Note that adding or subtracting 2 preserves parity: an even digit stays even and an odd digit stays odd. So the even digits of the new number are exactly the transformed versions of the original even digits — a shortcut that skips rewriting the whole number.
- Work left to right and write the new number out before answering. Attempting to track the transformation mentally across seven digits is where errors occur.
- Read the final instruction carefully: the question asks for a sum of selected digits, not the new number itself.
Topics covered: Number Operations Reasoning