In how many different ways can 840 be expressed as a product of two positive factors?

Basic Numeracy ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025

View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)

Question

In how many different ways can 840 be expressed as a product of two positive factors?

  1. A. 20
  2. B. 16 (Correct answer)
  3. C. 10
  4. D. 12

Correct Answer

Option B — 16

Detailed Solution & Explanation

The correct answer is 16.

Key Points

  • Factorise: 840 = 2³ × 3 × 5 × 7.
  • The number of divisors = (3 + 1)(1 + 1)(1 + 1)(1 + 1) = 4 × 2 × 2 × 2 = 32.
  • Each unordered pair of factors uses up two divisors, so the number of ways = 32 ÷ 2 = 16.

Additional Information

  • Halving is valid here because 840 is not a perfect square, so no divisor pairs with itself and the 32 divisors split cleanly into 16 pairs.
  • For a perfect square the count would be (d + 1)/2, since the square root pairs with itself.
  • Sample pairs: 1 × 840, 2 × 420, 3 × 280, 4 × 210, 5 × 168, 6 × 140, 7 × 120, 8 × 105, and so on to 20 × 42, 21 × 40, 24 × 35, 28 × 30.

*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*

Topics covered: Factors Worked Solution