Ram, while going to school, reduces his speed to 4/5th of his actual speed and reaches 15 minutes late. Find the actual time of R…
Quantitative Aptitude ·Previously asked in JKSSB Junior Assistant 2026
View the full solved paper: JKSSB Junior Assistant PYQ
Question
Ram, while going to school, reduces his speed to 4/5th of his actual speed and reaches 15 minutes late. Find the actual time of Ram.
- A. 45 minutes
- B. 60 minutes (Correct answer)
- C. 30 minutes
- D. 75 minutes
Correct Answer
Option B — B
Detailed Solution & Explanation
The correct answer is Option B.
Key Points
- When speed becomes 4/5 of usual, time becomes the reciprocal, 5/4 of usual (speed and time are inversely proportional for a fixed distance).
- Extra time = 5/4·T − T = T/4, and this equals the 15-minute delay:
- T/4 = 15 → T = 60 minutes.
- So Ram's actual (usual) time is 60 minutes.
Exam Tip
- if speed becomes a/b of normal, time becomes b/a of normal; the extra time = (b/a − 1)·usual time.
- Set it equal to the given delay and solve.
Additional Information
- Speed and time are inversely proportional over a fixed distance: at 4/5 speed, time becomes 5/4 of usual, so the extra 1/4 of the usual time equals the 15-minute delay.
- Usual time is therefore 60 minutes.
- The general result: if speed becomes a/b of usual, the extra time is (b − a)/a of the usual time — worth memorising for this very common question type.
Topics covered: Quantitative Aptitude