Which two numbers need to be swapped to make this equation correct? 20÷5×3 + 10 − 4 = 20

Reasoning & General Intelligence ·Previously asked in SSC CGL 2025

View the full solved paper: SSC CGL 2025 Tier II (19 Jan 2026)

Question

Which two numbers need to be swapped to make this equation correct? 20÷5×3 + 10 − 4 = 20

  1. A. 20 and 10
  2. B. 3 and 4
  3. C. 4 and 5 (Correct answer)
  4. D. 5 and 10

Correct Answer

Option C — 4 and 5

Detailed Solution & Explanation

The correct answer is 4 and 5.

Key Points

  • As printed, 20 ÷ 5 × 3 + 10 − 4 evaluates to:
    • 20 ÷ 5 = 4, 4 × 3 = 12, 12 + 10 = 22, 22 − 4 = 18, not 20.
  • Swapping 4 and 5 gives 20 ÷ 4 × 3 + 10 − 5:
    • 20 ÷ 4 = 5, 5 × 3 = 15, 15 + 10 = 25, 25 − 5 = 20

Additional Information

  • Test each option by substitution rather than reasoning abstractly — with only four candidates it is faster and certain.
  • BODMAS still governs after the swap: division and multiplication before addition and subtraction, each pair left to right.
  • A useful filter is to check whether a swap changes the divisibility. Here 20 ÷ 4 stays whole, whereas swapping 20 and 10 would give 10 ÷ 5 × 3 and a very different scale.
  • Only the numbers move in this question type; the operators stay where they are, which distinguishes it from operator-substitution questions.

Topics covered: Equation Correction BODMAS