If 1³ + 2³ + 3³ + ......... + x³ = 441, Find the value of x:
Basic Numeracy ·Previously asked in JKPSC Combined Competitive Examination (JKCCE) 2025
View the full solved paper: JKCCE Prelims 2025 - GS Paper II (Set B)
Question
If 1³ + 2³ + 3³ + ......... + x³ = 441,
Find the value of x:
- A. 21
- B. 6 (Correct answer)
- C. 20
- D. 7
Correct Answer
Option B — 6
Detailed Solution & Explanation
The correct answer is 6.
Key Points
- Use the identity 1³ + 2³ + … + x³ = [x(x + 1)/2]².
- So [x(x + 1)/2]² = 441, giving x(x + 1)/2 = √441 = 21.
- Then x(x + 1) = 42, and since 6 × 7 = 42, we get x = 6.
Additional Information
- Check directly: 1 + 8 + 27 + 64 + 125 + 216 = 441 ✓
- The distractor 21 is the value of the *sum* 1 + 2 + … + x, not of x itself — a step short of the answer.
*Ministry of Papers worked solution. The Commission has not yet published the official key for this paper; this answer will be reconciled with it on release.*
Topics covered: Series & Sums Worked Solution